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Nov 2013 p11 q9
851
In an arithmetic progression the sum of the first ten terms is 400 and the sum of the next ten terms is 1000. Find the common difference and the first term.
Solution
The sum of the first ten terms of an arithmetic progression is given by:
\(S_{10} = \frac{10}{2} (2a + 9d) = 400\)
This simplifies to:
\(2a + 9d = 80\)
The sum of the next ten terms (terms 11 to 20) is given by:
