Let the first term be \(a\) and the common difference be \(d\).

The fifth term is given by:

\(a + 4d = 197\)

The sum of the first ten terms is given by:

\(\frac{10}{2} [2a + 9d] = 2040\)

Simplifying the sum equation:

\(5(2a + 9d) = 2040\)

\(2a + 9d = 408\)

We now have two equations:

1. \(a + 4d = 197\)

2. \(2a + 9d = 408\)

Multiply the first equation by 2:

\(2a + 8d = 394\)

Subtract this from the second equation:

\((2a + 9d) - (2a + 8d) = 408 - 394\)

\(d = 14\)

Thus, the common difference is 14.