Answer: amplitude \(4\); period \(60^\circ\) or \(\dfrac{\pi}{3}\).

For \(y=3\cos2x-1\), the midline is \(y=-1\), the amplitude is \(3\), and the period is

\(\frac{360^\circ}{2}=180^\circ.\)

The graph starts at \(y=2\) when \(x=0^\circ\), reaches a minimum of \(-4\) at \(x=90^\circ\), returns to \(2\) at \(x=180^\circ\), reaches another minimum at \(x=270^\circ\), and finishes at \(2\) when \(x=360^\circ\).

For \(y=4\sin6x\), the amplitude is

\(4.\)

The period is

\(\frac{360^\circ}{6}=60^\circ.\)

Equivalently, in radians this is \(\frac{\pi}{3}\).