The first, second and third terms of an arithmetic progression are \(a, 2a\) and \(a^2\) respectively, where \(a\) is a positive constant.
Find the sum of the first 50 terms of the progression.
Solution
Given the arithmetic progression with terms \(a, 2a, a^2\), the common difference \(d\) is:
\(d = 2a - a = a\)
\(d = a^2 - 2a\)
Equating the two expressions for \(d\):
\(a = a^2 - 2a\)
\(a^2 - 3a = 0\)
\(a(a - 3) = 0\)
Since \(a\) is positive, \(a = 3\).
Thus, \(d = 3\).
The sum of the first 50 terms \(S_{50}\) is given by:
\(S_{50} = \frac{50}{2} (2a + 49d)\)
Substitute \(a = 3\) and \(d = 3\):
\(S_{50} = 25 (2 \times 3 + 49 \times 3)\)
\(S_{50} = 25 (6 + 147)\)
\(S_{50} = 25 \times 153\)
\(S_{50} = 3825\)
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