The volume, \(V\), and surface area, \(S\), of a sphere of radius \(r\) are given by \(V=\dfrac43\pi r^3\) and \(S=4\pi r^2\), respectively.

The volume of a sphere increases at a rate of \(200\text{ cm}^3\) per second. At the instant when the radius of the sphere is \(10\) cm, find

(i) the rate of increase of the radius of the sphere,

(ii) the rate of increase of the surface area of the sphere.