The first term of the arithmetic progression is given as \(a = 6\).

The second term is \(2\), so the common difference \(d\) is \(2 - 6 = -4\).

The formula for the sum of the first \(n\) terms of an arithmetic progression is:

\(S_n = \frac{n}{2} (2a + (n-1)d)\)

Substitute \(n = 80\), \(a = 6\), and \(d = -4\) into the formula:

\(S_{80} = \frac{80}{2} (2 \times 6 + 79 \times (-4))\)

\(S_{80} = 40 (12 - 316)\)

\(S_{80} = 40 \times (-304)\)

\(S_{80} = -12,160\)