Answer: \(x=\pm\sqrt3\); \(B\) is \(3\times2\); \(CB\ne BC\) because their orders are different.

A matrix has no inverse when its determinant is zero.

For \(A\),

\(\det A=(x+3)(x-3)-(-x)(2x).\)

So

\(\det A=x^2-9+2x^2=3x^2-9.\)

Set this equal to zero:

\(3x^2-9=0.\)

Thus

\(x^2=3,\)

so

\(\boxed{x=\pm\sqrt3}.\)

The matrix \(B\) has 3 rows and 2 columns, so its order is

\(\boxed{3\times2}.\)

The product \(BC\) has order \(3\times3\), while \(CB\) has order \(2\times2\). Since the products have different orders, they cannot be equal. Therefore \(CB\ne BC\).