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0606 P13 - Jun 2019 - Q6 - 10 marks
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(a)(i) Show that \(\operatorname{sec}\theta-\dfrac{\tan\theta}{\operatorname{cosec}\theta}=\cos\theta\).

(a)(ii) Solve \(\operatorname{sec}2\theta-\dfrac{\tan2\theta}{\operatorname{cosec}2\theta}=\dfrac{\sqrt3}{2}\) for \(0^\circ\leq\theta\leq180^\circ\).

(b) Solve \(2\sin^2\left(\phi+\frac{\pi}{3}\right)=1\) for \(0\lt \phi\lt 2\pi\) radians.

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