0606 P12 - Mar 2019 - Q11 - 10 marks
8240
(a) Solve the equation \(\sin x\cos x=\dfrac12\tan x\), for \(0^\circ\leq x\leq180^\circ\).
(b) (i) Prove the identity
\(\operatorname{sec}\theta-\frac{\sin\theta}{\operatorname{cot}\theta}\equiv\cos\theta.\)
(ii) Hence solve
\(\operatorname{sec}3\theta-\frac{\sin3\theta}{\cot3\theta}=\frac12\)
for \(-\dfrac{2\pi}{3}\leq\theta\leq\dfrac{2\pi}{3}\).
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