For Scheme A, the amount of waste recycled each month forms an arithmetic sequence with the first term \(a = 2.5\) and common difference \(d = 0.16\).

The sum of the first \(n\) terms of an arithmetic sequence is given by:

\(S_n = \frac{n}{2} (2a + (n-1)d)\)

Substituting \(n = 24\), \(a = 2.5\), and \(d = 0.16\):

\(S_{24} = \frac{24}{2} (2 \times 2.5 + 23 \times 0.16)\)

\(S_{24} = 12 (5 + 3.68)\)

\(S_{24} = 12 \times 8.68 = 104.16\)

Rounding to the nearest whole number, the total amount is 104 tonnes.

For Scheme B, the amount of waste recycled each month forms a geometric sequence with the first term \(a = 2.5\) and common ratio \(r = 1.06\).

The sum of the first \(n\) terms of a geometric sequence is given by:

\(S_n = a \frac{r^n - 1}{r - 1}\)

Substituting \(n = 24\), \(a = 2.5\), and \(r = 1.06\):

\(S_{24} = 2.5 \frac{1.06^{24} - 1}{1.06 - 1}\)

\(S_{24} = 2.5 \frac{4.29187072 - 1}{0.06}\)

\(S_{24} = 2.5 \times 54.864512\)

\(S_{24} = 137.16128\)

Rounding to the nearest whole number, the total amount is 137 tonnes.