It is given that

\(y=(2x-1)\sqrt{4x+3}.\)

(a) Show that

\(\frac{dy}{dx}=\frac{4(Ax+B)}{\sqrt{4x+3}},\)

where \(A\) and \(B\) are constants to be found.

(b) Find the \(x\)-coordinate of the stationary point and determine its nature.