Answer: \(p=5+2\sqrt5\).

Since the point lies on the curve, substitute \(x=1-\sqrt5\):

\(p=\frac{10+2\sqrt5}{(1-\sqrt5)^2}.\)

Now

\((1-\sqrt5)^2=1-2\sqrt5+5=6-2\sqrt5.\)

So

\(p=\frac{10+2\sqrt5}{6-2\sqrt5}=\frac{5+\sqrt5}{3-\sqrt5}.\)

Rationalise the denominator:

\(p=\frac{(5+\sqrt5)(3+\sqrt5)}{(3-\sqrt5)(3+\sqrt5)}.\)

The denominator is \(9-5=4\), and the numerator is

\(15+5\sqrt5+3\sqrt5+5=20+8\sqrt5.\)

Hence

\(p=\frac{20+8\sqrt5}{4}=5+2\sqrt5.\)

Therefore

\(\boxed{p=5+2\sqrt5}.\)