0606 P11 - Jun 2020 - Q5 - 6 marks
8101
Find the equation of the tangent to the curve
\(y=\frac{\ln(3x^2-1)}{x+2}\)
at the point where \(x=1\). Give your answer in the form \(y=mx+c\), where \(m\) and \(c\) are constants correct to 3 decimal places.
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