0606 P22 - Jun 2022 - Q12 - 7 marks
7834
A curve is such that \(\displaystyle \frac{d^2y}{dx^2}=\left(\frac{\sqrt{x}+1}{\sqrt[4]{x}}\right)^2\). Given that the gradient of the curve is \(\frac43\) at the point \((1,-1)\), find the equation of the curve.
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