The function given is \(f(x) = 2x + 1\).

To find the inverse function \(f^{-1}(x)\), we set \(y = 2x + 1\) and solve for \(x\):

\(y = 2x + 1\)

\(y - 1 = 2x\)

\(x = \frac{1}{2}(y - 1)\)

Thus, \(f^{-1}(x) = \frac{1}{2}(x - 1)\).

The graph of \(y = f(x) = 2x + 1\) is a straight line with a slope of 2, starting from \((0, 1)\).

The graph of \(y = f^{-1}(x) = \frac{1}{2}(x - 1)\) is a straight line with a slope of \(\frac{1}{2}\), starting from \((1, 0)\).

These two graphs are reflections of each other across the line \(y = x\).