The volume \(V\text{ cm}^3\) of a sphere of radius \(r\text{ cm}\) is given by

\(V=\frac43\pi r^3.\)

At the instant when \(r=6\), the volume is increasing at a rate of \(24\text{ cm}^3\text{s}^{-1}\). Find the rate at which the radius is increasing at this instant, giving your answer in terms of \(\pi\).