The equation of a curve is \(y=\frac{\mathrm{e}^{-3 x+2}}{x+1}\) where \(x\lt -1\). (a) Show that \(\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\mathrm{e}^{-3 x+2}}{(x+1)^{2}}(A x+B) \quad\) where \(A\) and \(B\) are integers to be found. (b) Hence show that there is only one stationary point on the curve and find its exact coordinates.