0606 P22 - Mar 2025 - Q11 - 4 marks
7205
Solve the equation \(\cot(y+1.5)=3\), where \(y\) is in radians and \(0\lt y\lt 6\).
Solution
Answer: \(y=1.96\) or \(y=5.10\).
Use the standard trigonometric identities and make sure the final angles are chosen from the interval given in the question.
Since \(\cot(y+1.5)=3\),
\(\tan(y+1.5)=\frac13.\)
Let \(u=y+1.5\). Since \(0\lt y\lt 6\),
\(1.5\lt u\lt 7.5.\)
The principal value is
\(\tan^{-1}\left(\frac13\right)=0.32175\ldots.\)
In the interval \(1.5\lt u\lt 7.5\), the solutions are
\(u=0.32175\ldots+\pi\quad\text{and}\quad u=0.32175\ldots+2\pi.\)
Therefore
\(y=1.963\ldots\quad\text{or}\quad y=5.105\ldots.\)
So
\(y=1.96\quad\text{or}\quad y=5.10.\)
This gives the required answer: \(y=1.96\) or \(y=5.10\).