0606 P22 - Mar 2025 - Q8 - 7 marks
7202
(a) Show that \(\frac{\sin\theta\tan^2\theta}{1+\tan^2\theta}\) can be written as \(\sin^3\theta\).
(b) Hence solve the equation \(\frac{\sin3x\tan^23x}{1+\tan^23x}=\frac18\) for \(-180^\circ\leqslant x\leqslant180^\circ\).
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