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9231 P31 - Nov 2020 - Q4 - 6 marks
7020

The diagram shows the cross-section \(A B C D\) of a uniform solid object which is formed by removing a cone with cross-section \(D C E\) from the top of a larger cone with cross-section \(A B E\). The perpendicular distance between \(A B\) and \(D C\) is \(h\), the diameter \(A B\) is \(6 r\) and the diameter \(D C\) is \(2 r\).
(a) Find an expression, in terms of \(h\), for the distance of the centre of mass of the solid object from \(A B\).

The object is freely suspended from the point \(B\) and hangs in equilibrium. The angle between \(A B\) and the downward vertical through \(B\) is \(\theta\).
(b) Given that \(h=\frac{13}{4} r\), find the value of \(\tan \theta\).

9231_w20_qp_31_q4 diagram
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