The curve \(C\) has polar equation \(r=1+\sin \theta\) for \(-\frac{1}{2} \pi \leqslant \theta \leqslant \frac{1}{2} \pi\). Draw a sketch of \(C\).

The area of the region enclosed by the initial line, the half-line \(\theta=\frac{1}{2} \pi\), and the part of \(C\) for which \(\theta\) is positive, is denoted by \(A_{1}\). The area of the region enclosed by the initial line, and the part of \(C\) for which \(\theta\) is negative, is denoted by \(A_{2}\). Find the ratio \(A_{1}: A_{2}\), giving your answer correct to 1 decimal place.