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9231 P21 - Nov 2018 - Q11O - 12 marks
6091

Question 11 OR alternative.

A machine is used to produce metal rods. When the machine is working efficiently, the lengths, \(x\ \mathrm{cm}\), of the rods have a normal distribution with mean \(150\ \mathrm{cm}\) and standard deviation \(1.2\ \mathrm{cm}\). The machine is checked regularly by taking random samples of \(200\) rods. The latest results are shown in the following table.

Interval \(146 \leq x < 147\) \(147 \leq x < 148\) \(148 \leq x < 149\) \(149 \leq x < 150\) \(150 \leq x < 151\) \(151 \leq x < 152\) \(152 \leq x < 153\) \(153 \leq x < 154\)
Observed frequency 1 2 23 52 69 36 15 2

As a first check, the sample is used to calculate an estimate for the mean.

(i) Show that an estimate for the mean from this sample is close to \(150\ \mathrm{cm}\).

As a second check, the results are tested for goodness of fit of the normal distribution with mean \(150\ \mathrm{cm}\) and standard deviation \(1.2\ \mathrm{cm}\). The relevant expected frequencies are shown in the following table.

Interval \(x < 147\) \(147 \leq x < 148\) \(148 \leq x < 149\) \(149 \leq x < 150\) \(150 \leq x < 151\) \(151 \leq x < 152\) \(152 \leq x < 153\) \(153 \leq x\)
Observed frequency 1 2 23 52 69 36 15 2
Expected frequency 1.24 8.32 30.94 59.50 59.50 30.94 8.32 1.24

(ii) Show how the expected frequency for \(151 \leq x < 152\) is obtained.

(iii) Test, at the \(5\%\) significance level, the goodness of fit of the normal distribution to the results.

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