(i) To find the \(x\)-coordinate of \(A\), set \(\tan x = \cos x\).

This implies \(\sin x = \cos^2 x\).

Using the identity \(\cos^2 x = 1 - \sin^2 x\), we have \(\sin x = 1 - \sin^2 x\).

Rearrange to form a quadratic equation: \(\sin^2 x + \sin x - 1 = 0\).

Solving this quadratic equation gives \(\sin x = 0.618\).

Thus, \(x = \sin^{-1}(0.618) = 0.666\).

(ii) For point \(B\), the \(x\)-coordinate is \(\pi - 0.666 = 2.475\).

Calculate the \(y\)-coordinate using \(y = \tan(2.475)\) or \(y = \cos(2.475)\).

This gives \(y = -0.787\).

Therefore, the coordinates of \(B\) are \((2.48, -0.787)\).