The function \(f : x \mapsto 4 - 3 \sin x\) is defined for the domain \(0 \leq x \leq 2\pi\).
(i) Solve the equation \(f(x) = 2\). [3]
(ii) Sketch the graph of \(y = f(x)\). [2]
(iii) Find the set of values of \(k\) for which the equation \(f(x) = k\) has no solution. [2]
The function \(g : x \mapsto 4 - 3 \sin x\) is defined for the domain \(\frac{1}{2}\pi \leq x \leq A\).
(iv) State the largest value of \(A\) for which \(g\) has an inverse. [1]
(v) For this value of \(A\), find the value of \(g^{-1}(3)\). [2]
Solution
(i) Solve \(4 - 3 \sin x = 2\) to get \(3 \sin x = 2\), so \(\sin x = \frac{2}{3}\). The solutions are \(x = 0.730\) or \(x = 2.41\).
(ii) The graph of \(y = 4 - 3 \sin x\) should show one complete oscillation, correctly shaped and positioned in the first quadrant.
(iii) The equation \(f(x) = k\) has no solution for \(k < 1\) or \(k > 7\).
(iv) The largest value of \(A\) for which \(g\) has an inverse is \(A = \frac{3\pi}{2}\).
(v) For \(g^{-1}(3)\), solve \(3 = 4 - 3 \sin x\) to get \(\sin x = \frac{1}{3}\). Thus, \(g^{-1}(3) = 2.80\).
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