Prove the identity \((\sin \theta + \cos \theta)(1 - \sin \theta \cos \theta) \equiv \sin^3 \theta + \cos^3 \theta\).
Solution
Start with the left-hand side (LHS):
\((\sin \theta + \cos \theta)(1 - \sin \theta \cos \theta)\)
Expand the expression:
\(= \sin \theta + \cos \theta - \sin^2 \theta \cos \theta - \sin \theta \cos^2 \theta\)
Factor out common terms:
\(= \sin \theta(1 - \cos^2 \theta) + \cos \theta(1 - \sin^2 \theta)\)
Use the identity \(1 - \cos^2 \theta = \sin^2 \theta\) and \(1 - \sin^2 \theta = \cos^2 \theta\):
\(= \sin^3 \theta + \cos^3 \theta\)
Thus, the identity is proven: \((\sin \theta + \cos \theta)(1 - \sin \theta \cos \theta) \equiv \sin^3 \theta + \cos^3 \theta\).
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