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9709 P1 - Nov 2002 - Q5 - 6 marks
474

(i) Show that the equation \(3 \tan \theta = 2 \cos \theta\) can be expressed as \(2 \sin^2 \theta + 3 \sin \theta - 2 = 0\).

(ii) Hence solve the equation \(3 \tan \theta = 2 \cos \theta\), for \(0^\circ \leq \theta \leq 360^\circ\).

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