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9709 P11 - Jun 2011 - Q5 - 6 marks
465

(i) Show that the equation \(2 \tan^2 \theta \sin^2 \theta = 1\) can be written in the form \(2 \sin^4 \theta + \sin^2 \theta - 1 = 0\).

(ii) Hence solve the equation \(2 \tan^2 \theta \sin^2 \theta = 1\) for \(0^\circ \leq \theta \leq 360^\circ\).

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