9709 P11 - Nov 2018 - Q5 - 6 marks
444
(i) Show that the equation \(\frac{\cos \theta - 4}{\sin \theta} - \frac{4 \sin \theta}{5 \cos \theta - 2} = 0\) may be expressed as \(9 \cos^2 \theta - 22 \cos \theta + 4 = 0\).
(ii) Hence solve the equation \(\frac{\cos \theta - 4}{\sin \theta} - \frac{4 \sin \theta}{5 \cos \theta - 2} = 0\) for \(0^\circ \leq \theta \leq 360^\circ\).
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