Browsing as Guest. Progress, bookmarks and attempts are disabled.
Log in to track your work.
May/June 2026 p42 q5
4339
The points \(A\) and \(B\) are at the same vertical height \(h\text{ m}\) above horizontal ground. A particle \(P\) is released from rest from \(A\). One second later, a particle \(Q\) is projected vertically downwards from \(B\) with speed \(18\text{ m s}^{-1}\).
Given that \(P\) and \(Q\) reach the ground at the same time, find the value of \(h\).
Solution
✔ Checked by expert
Let the time taken by \(P\) to reach the ground be \(T\text{ s}\).
Then the time taken by \(Q\) is \((T-1)\text{ s}\).