To solve this problem, we need to resolve forces in two directions: radially and tangentially.

1. Radially, the forces are resolved as:

\(T \cos 25^{\circ} = 40 + R \cos 50^{\circ}\)

2. Tangentially, the forces are resolved as:

\(R \sin 50^{\circ} = T \sin 25^{\circ}\)

From these two equations, we can solve for the tension \(T\) and the normal reaction \(R\).

3. Solving the equations:

From the tangential equation:

\(R \sin 50^{\circ} = T \sin 25^{\circ}\)

From the radial equation:

\(T \cos 25^{\circ} = 40 + R \cos 50^{\circ}\)

4. Solving these equations simultaneously gives:

\(T = 72.5 \text{ N}\)

\(R = 40 \text{ N}\)