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Nov 2011 p41 q4
4064
A, B, and C are three points on a line of greatest slope of a smooth plane inclined at an angle of \(\theta^\circ\) to the horizontal. A is higher than B and B is higher than C, and the distances AB and BC are 1.76 m and 2.16 m respectively. A particle slides down the plane with constant acceleration \(a \, \text{m s}^{-2}\). The speed of the particle at A is \(u \, \text{m s}^{-1}\) (see diagram). The particle takes 0.8 s to travel from A to B and takes 1.4 s to travel from A to C. Find
the values of \(u\) and \(a\),
the value of \(\theta\).
Solution
To solve for \(u\) and \(a\), we use the equations of motion. For the segment AB, we have:
\(s = ut + \frac{1}{2}at^2\)
Substituting the known values for AB:
\(1.76 = 0.8u + \frac{1}{2} \times a \times (0.8)^2\)