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Nov 2019 p41 q4
4060
Two blocks A and B of masses 4 kg and 5 kg respectively are joined by a light inextensible string. The blocks rest on a smooth plane inclined at an angle \(\alpha\) to the horizontal, where \(\tan \alpha = \frac{7}{24}\). The string is parallel to a line of greatest slope of the plane with B above A. A force of magnitude 36 N acts on B, parallel to a line of greatest slope of the plane (see diagram).
Find the acceleration of the blocks and the tension in the string. [5]
At a particular instant, the speed of the blocks is 1 m s-1. Find the time, after this instant, that it takes for the blocks to travel 0.65 m. [2]
Solution
(i) Apply Newton's second law to the system:
For block A: \(T - 4g \times \frac{7}{25} = 4a\)
For block B: \(36 - T - 5g \times \frac{7}{25} = 5a\)
For the system: \(36 - 5g \times \frac{7}{25} - 4g \times \frac{7}{25} = 9a\)
Solving these equations gives \(a = 1.2 \text{ ms}^{-2}\) and \(T = 16 \text{ N}\).