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Nov 2019 p41 q3
4016
A block of mass 3 kg is at rest on a rough plane inclined at 60° to the horizontal. A force of magnitude 15 N acting up a line of greatest slope of the plane is just sufficient to prevent the block from sliding down the plane.
Find the coefficient of friction between the block and the plane.
The force of magnitude 15 N is now replaced by a force of magnitude X N acting up the line of greatest slope.
Find the greatest value of X for which the block does not move.
Solution
(i) The normal reaction force \(R\) is given by:
\(R = 3g \cos 60^{\circ}\)
Using the equation for frictional force \(F = \mu R\), we resolve forces parallel to the plane: