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June 2021 p42 q4
4014
A particle of mass 12 kg is stationary on a rough plane inclined at an angle of 25° to the horizontal. A pulling force of magnitude \(P\) N acts at an angle of 8° above a line of greatest slope of the plane. This force is used to keep the particle in equilibrium. The coefficient of friction between the particle and the plane is 0.3.
Find the greatest possible value of \(P\).
Solution
To solve for the greatest possible value of \(P\), we resolve the forces parallel and perpendicular to the plane.
1. Resolve forces perpendicular to the plane:
\(12g \cos 25 = R + P \sin 8\)
2. Resolve forces parallel to the plane:
\(P \cos 8 = F + 12g \sin 25\)
3. The frictional force \(F\) is given by:
\(F = 0.3R\)
4. Substitute \(F = 0.3R\) into the parallel force equation:
\(P \cos 8 = 0.3R + 12g \sin 25\)
5. Substitute \(R = 12g \cos 25 - P \sin 8\) from the perpendicular equation into the parallel equation: