9709 P43 - Jun 2011 - Q5
3978
A small block of mass 1.25 kg is on a horizontal surface. Three horizontal forces, with magnitudes and directions as shown in the diagram, are applied to the block. The angle \(\theta\) is such that \(\cos \theta = 0.28\) and \(\sin \theta = 0.96\). A horizontal frictional force also acts on the block, and the block is in equilibrium.
- Show that the magnitude of the frictional force is 7.5 N and state the direction of this force.
- Given that the block is in limiting equilibrium, find the coefficient of friction between the block and the surface.
- The force of magnitude 6.1 N is now replaced by a force of magnitude 8.6 N acting in the same direction, and the block begins to move. Find the magnitude and direction of the acceleration of the block.
