First, resolve the forces vertically to find the normal reaction \(R\):

\(R = 300g - X \sin \alpha\)

Given \(\sin \alpha = 0.28\), we find \(\alpha \approx 16.26^\circ\).

Now, resolve horizontally:

\(0.96X - F = 0\)

where \(F\) is the frictional force, \(F = 0.5R\).

Substitute \(F\) into the equation:

\(0.96X = 0.5(300g - X \sin \alpha)\)

Solving for \(X\):

\(0.96X = 0.5(300 \times 9.8 - X \times 0.28)\)

\(0.96X = 1470 - 0.14X\)

\(1.1X = 1470\)

\(X = \frac{1470}{1.1} \approx 1363.63\)

Rounding down to the nearest whole number, \(X = 1360\).