Using Newton's second law for particle P:

\(10 - 0.5g - T = 0.5a\)

For particle Q:

\(T - 0.3g = 0.3a\)

For the system of both particles:

\(10 - 0.5g - 0.3g = 0.8a\)

Solving for acceleration \(a\):

\(10 - 0.8g = 0.8a\)

\(a = \frac{10 - 0.8 \times 9.8}{0.8} = 2.5 \text{ m/s}^2\)

Substitute \(a = 2.5\) into the equation for Q:

\(T - 0.3 \times 9.8 = 0.3 \times 2.5\)

\(T = 0.3 \times 9.8 + 0.75 = 3.75 \text{ N}\)