(i) To find the time after projection at which P hits the ground, we use the equation of motion:

\(v = u - gt\)

where \(v = -11\) m/s (final velocity when hitting the ground), \(u = 11\) m/s (initial velocity), and \(g = 10\) m/s² (acceleration due to gravity).

Substitute the values:

\(-11 = 11 - 10t\)

Solve for \(t\):

\(-11 = 11 - 10t\)

\(-22 = -10t\)

\(t = 2.2 \text{ seconds}\)

(ii) To find the values of \(h\) and \(V\):

For particle Q, using the equation:

\(h = 0 + \frac{1}{2} g t^2\)

Substitute \(g = 10\) m/s² and \(t = 2.2\) s:

\(h = \frac{1}{2} \times 10 \times (2.2)^2 = 24.2 \text{ m}\)

For the speed \(V\) of Q when it hits the ground:

\(V = 0 + gt\)

Substitute \(g = 10\) m/s² and \(t = 2.2\) s:

\(V = 10 \times 2.2 = 22 \text{ m/s}\)