To solve for V and H, we use the equations of motion under gravity. Assume acceleration due to gravity is \(g\).

(i) Finding \(V\):

Using the equation \(v^2 = u^2 + 2gs\), where \(u\) is the initial velocity, \(v\) is the final velocity, and \(s\) is the displacement:

For the section from 35 m above the ground to the ground:

\(V^2 = (V - 10)^2 + 2g \times 35\)

Expanding and simplifying:

\(V^2 = V^2 - 20V + 100 + 70g\)

\(20V = 100 + 70g\)

Assuming \(g = 10 \text{ m s}^{-2}\):

\(20V = 100 + 700\)

\(20V = 800\)

\(V = 40\)

(ii) Finding \(H\):

Using the equation \(v^2 = u^2 + 2gs\) for the entire fall from H to the ground:

\(40^2 = 0^2 + 2gH\)

\(1600 = 20H\)

\(H = 80\)