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Nov 2023 p43 q1
3849
A particle is projected vertically upwards from horizontal ground with a speed of \(u \text{ m s}^{-1}\). The particle has height \(s\) m above the ground at times 3 seconds and 4 seconds after projection.
Find the value of \(u\) and the value of \(s\).
Solution
Using the SUVAT equation for vertical motion: \(s = ut - \frac{1}{2}gt^2\), where \(g = 10 \text{ m s}^{-2}\).
At \(t = 3\) seconds, \(s = 3u - 5 \times 9\).
At \(t = 4\) seconds, \(s = 4u - 5 \times 16\).
Equating the two expressions for \(s\):
\(3u - 45 = 4u - 80\)
Solving for \(u\):
\(3u - 4u = -80 + 45\)
\(-u = -35\)
\(u = 35\)
Substitute \(u = 35\) back into one of the equations for \(s\):