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N0V 2009 p Q10i
379
The diagram shows the line \(2y = x + 5\) and the curve \(y = x^2 - 4x + 7\), which intersect at the points \(A\) and \(B\). Findthe \(x\)-coordinates of \(A\) and \(B\),
Solution
Given the equations:
Line: \(2y = x + 5\)
Curve: \(y = x^2 - 4x + 7\)
Substitute \(y\) from the line equation into the curve equation:
\(y = \frac{x + 5}{2}\)
Substitute into the curve equation:
\(\frac{x + 5}{2} = x^2 - 4x + 7\)
Multiply through by 2 to eliminate the fraction:
\(x + 5 = 2x^2 - 8x + 14\)
Rearrange to form a quadratic equation:
\(2x^2 - 9x + 9 = 0\)
Factor or use the quadratic formula to solve for \(x\):