The forces acting at point A are 100 N to the left, and two 50 N forces at angles \(\alpha\) to the horizontal. The horizontal component of each 50 N force is \(50 \cos \alpha\).

The total horizontal component of the two 50 N forces is \(2 \times 50 \cos \alpha = 100 \cos \alpha\).

Given \(\cos \alpha = \frac{4}{5}\), the total horizontal component becomes \(100 \times \frac{4}{5} = 80\) N.

The resultant force is the difference between the 100 N force and the total horizontal component of the two 50 N forces:

\(100 - 80 = 20 \text{ N}\)

The direction of the resultant force is to the left.