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Nov 2009 p41 q3
3701
Two forces have magnitudes \(P\) N and \(Q\) N. The resultant of the two forces has magnitude 12 N and acts in a direction 40° clockwise from the force of magnitude \(P\) N and 80° anticlockwise from the force of magnitude \(Q\) N (see diagram). Find the value of \(Q\).
Solution
To find the value of \(Q\), we resolve the forces and use trigonometric identities. The angles between the forces and the resultant are given as 40° and 80°.
Using the cosine rule for the triangle formed by the forces and the resultant:
\(Q - P \cos 60^{\circ} = 12 \cos 80^{\circ}\)
\(P \sin 60^{\circ} = 12 \sin 80^{\circ}\)
From the first equation, we can express \(Q\) in terms of \(P\):