First, resolve the forces in the x-direction and y-direction:

\(X = 160 + 250 \cos \alpha = 160 + 250 \times 0.96 = 400 \text{ N}\)

\(Y = 370 - 250 \sin \alpha = 370 - 250 \times 0.28 = 300 \text{ N}\)

Calculate the magnitude of the resultant force \(R\) using Pythagoras' theorem:

\(R = \sqrt{X^2 + Y^2} = \sqrt{400^2 + 300^2} = \sqrt{160000 + 90000} = \sqrt{250000} = 500 \text{ N}\)

Calculate the angle \(\theta\) that the resultant makes with the x-direction using the tangent function:

\(\tan \theta = \frac{Y}{X} = \frac{300}{400} = 0.75\)

\(\theta = \arctan(0.75) \approx 36.9^\circ\)