Resolve the forces into their components along the x and y axes.

For the x-direction:

\(X = 12\cos 25^{\circ} - 8\cos 10^{\circ} = 2.9972\)

For the y-direction:

\(Y = 12\sin 25^{\circ} + 8\sin 10^{\circ} - 2 = 4.4606\)

The magnitude of the resultant force \(R\) is given by:

\(R = \sqrt{X^2 + Y^2} = \sqrt{(2.9972)^2 + (4.4606)^2} = 5.37\)

The angle \(\theta\) is given by:

\(\tan \theta = \frac{X}{Y} = \frac{2.9972}{4.4606}\)

\(\theta = \arctan\left(\frac{2.9972}{4.4606}\right) = 33.9^{\circ}\)