(i) To find the y-components of the forces, use the Pythagorean theorem:

\(Y_1^2 = 68^2 - (-60)^2\)

\(Y_1 = \sqrt{68^2 - 60^2} = 32\)

\(Y_2 = 75\) (since the force is vertical)

\(Y_3^2 = 100^2 - 96^2\)

\(Y_3 = \sqrt{100^2 - 96^2} = 28\)

Thus, the components in the positive y-direction are -32, 75, and -28.

(ii) The resultant force components are:

\(X = -60 + 0 + 96 = 36\)

\(Y = -32 + 75 - 28 = 15\)

The magnitude of the resultant force is:

\(R = \sqrt{X^2 + Y^2} = \sqrt{36^2 + 15^2} = 39 \text{ N}\)

The direction \(\theta\) is given by:

\(\theta = \arctan \left( \frac{Y}{X} \right) = \arctan \left( \frac{15}{36} \right) \approx 22.6^\circ\)

The direction is 22.6° anticlockwise from the positive x-axis.