To find the resultant force, resolve the forces horizontally and vertically.

For the horizontal component:

\(X = 7 - 8 \cos \alpha - 6 \sin \alpha\)

Given \(\sin \alpha = \frac{3}{5}\), use \(\cos \alpha = \frac{4}{5}\) (since \(\sin^2 \alpha + \cos^2 \alpha = 1\)).

\(X = 7 - 8 \times \frac{4}{5} - 6 \times \frac{3}{5} = -3\)

For the vertical component:

\(Y = 8 \sin \alpha - 6 \cos \alpha\)

\(Y = 8 \times \frac{3}{5} - 6 \times \frac{4}{5} = 0\)

The resultant force is \(\sqrt{X^2 + Y^2} = \sqrt{(-3)^2 + 0^2} = 3 \text{ N}\).

Since \(X = -3\), the direction is to the left.