(i) To find the total force in the direction of the river, resolve each force into its horizontal component:

\(X = 60 \cos 25^{\circ} + 50 \cos 15^{\circ}\)

Calculating gives:

\(X = 54.49 + 48.30 = 102.79 \text{ N}\)

Rounded to 103 N.

(ii) To find the magnitude and direction of the resultant force, resolve each force into its vertical component:

\(Y = 60 \sin 25^{\circ} - 50 \sin 15^{\circ}\)

Calculating gives:

\(Y = 25.35 - 12.94 = 12.41 \text{ N}\)

Now, use Pythagoras' theorem to find the magnitude:

\(R = \sqrt{X^2 + Y^2} = \sqrt{102.79^2 + 12.41^2}\)

\(R = \sqrt{10568.38 + 154.08} = \sqrt{10722.46} = 103.4 \text{ N}\)

To find the direction, use:

\(\alpha = \arctan\left(\frac{Y}{X}\right) = \arctan\left(\frac{12.41}{102.79}\right)\)

\(\alpha = 6.9^{\circ}\)