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June 2012 p43 q1
3610
A ring is threaded on a fixed horizontal bar. The ring is attached to one end of a light inextensible string which is used to pull the ring along the bar at a constant speed of 0.5 m s-1. The string makes a constant angle of 24° with the bar and the tension in the string is 6 N (see diagram). Find the work done by the tension in a period of 8 s.
Solution
The work done by the tension is calculated using the formula:
\(WD = Fd \cos \alpha\)
where \(F = 6 \text{ N}\) is the tension, \(d\) is the distance traveled, and \(\alpha = 24^\circ\) is the angle.
The distance \(d\) is given by the speed multiplied by time:
\(d = 0.5 \times 8 = 4 \text{ m}\)
Substituting the values into the work done formula: