The total mass of the cyclist and bicycle is 105 kg.

The initial speed is 5 m/s and the final speed is 10 m/s.

The kinetic energy gain is calculated as:

\(\text{KE gain} = \frac{1}{2} \times 105 \times (10^2 - 5^2) = \frac{1}{2} \times 105 \times (100 - 25) = \frac{1}{2} \times 105 \times 75 = 3937.5 \text{ J}\)

The work done against resistance is:

\(\text{WD against Resistance} = 50 \times 40 = 2000 \text{ J}\)

The total work done is the sum of the kinetic energy gain and the work done against resistance:

\(\text{Total WD} = 3937.5 + 2000 = 5937.5 \text{ J}\)